y^2-7y+29.3=0

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Solution for y^2-7y+29.3=0 equation:


Simplifying
y2 + -7y + 29.3 = 0

Reorder the terms:
29.3 + -7y + y2 = 0

Solving
29.3 + -7y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-29.3' to each side of the equation.
29.3 + -7y + -29.3 + y2 = 0 + -29.3

Reorder the terms:
29.3 + -29.3 + -7y + y2 = 0 + -29.3

Combine like terms: 29.3 + -29.3 = 0.0
0.0 + -7y + y2 = 0 + -29.3
-7y + y2 = 0 + -29.3

Combine like terms: 0 + -29.3 = -29.3
-7y + y2 = -29.3

The y term is -7y.  Take half its coefficient (-3.5).
Square it (12.25) and add it to both sides.

Add '12.25' to each side of the equation.
-7y + 12.25 + y2 = -29.3 + 12.25

Reorder the terms:
12.25 + -7y + y2 = -29.3 + 12.25

Combine like terms: -29.3 + 12.25 = -17.05
12.25 + -7y + y2 = -17.05

Factor a perfect square on the left side:
(y + -3.5)(y + -3.5) = -17.05

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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